Answer
$ \int^2_{-2} (-x^2 +4)dx$
Work Step by Step
Since $y_2 \geq y_1$, the integral is set up as
$\int^2_{-2} (y_2-y_1)dx$
$\int^2_{-2} ((2x+5) - (x^2 +2x +1))dx$
$ \int^2_{-2} (-x^2 +4)dx$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 7 - Applications of Integration - 7.1 Exercises - Page 442: 2
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