Answer
$\frac{15}{8}$
Work Step by Step
Setup the integration to find the area under the curve.
$\int_1^4 (\frac{4}{x^3})dx$
$\int_1^4 x^{-3} dx$
$[-2x^{-2} ]_1^4$, Integrate
$(-\frac{2}{16} +2)$, Evaluate the definite integral
$\frac{15}{8}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 7 - Applications of Integration - 7.1 Exercises - Page 442: 22
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