Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.1 Exercises - Page 442: 18

Answer

A=$10$

Work Step by Step

Setup the integration to find area between the two functions $\int_{-1}^1 [(-x^3 +2)-(x-3)]dx$ $\int_{-1}^1 (-x^3 -x+5)dx$, Integrate $[-\frac{1}{4}x^4 - \frac{1}{2}x^2 +5x]_{-1}^1$, Evaluate the definite integral $(-\frac{1}{4} -\frac{1}{2} +5) - ( -\frac{1}{4} - \frac{1}{2} - 5)$ $A=10$
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