Answer
$e^{-y}=cos(x)+C$
Work Step by Step
$y'-e^ysin(x)=0$
$\frac{dy}{dx}=e^ysin(x)$
$\int e^{-y}dy=\int sin(x)dx$
$-e^{-y}=-cos(x)+C'$
Or, $e^{-y}=cos(x)+C,$ $C=-C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - Review Exercises - Page 432: 36
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
