Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises: 36

Answer

$e^{-y}=cos(x)+C$

Work Step by Step

$y'-e^ysin(x)=0$ $\frac{dy}{dx}=e^ysin(x)$ $\int e^{-y}dy=\int sin(x)dx$ $-e^{-y}=-cos(x)+C'$ Or, $e^{-y}=cos(x)+C,$ $C=-C$
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