Answer
$y=Ce^{8x^{2}}$
Work Step by Step
$y'-16xy=0$
$\frac{dy}{dx}=16xy$
$\int \frac{1}{y}dy=\int 16xdx$
ln|y|=$8x^{2}+C_1$
$e^{8x^{2}+C_1}$=y
$y=Ce^{8x^{2}}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - Review Exercises - Page 432: 35
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