Answer
$8y^3=3x^4+C$
Work Step by Step
$\frac{dy}{dx}=\frac{x^3}{2y^2}$
Therefore, $2y^2dy=x^3dx$
$\int 2y^2dy=\int x^3dx$
Or, $\frac{2y^3}{3}=\frac{x^4}{4}+C'$
Multiplying both sides by 12 and taking $C=12C'$.
$$8y^3=3x^4+C$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - Review Exercises - Page 432: 34
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
