#### Answer

$8y^3=3x^4+C$

#### Work Step by Step

$\frac{dy}{dx}=\frac{x^3}{2y^2}$
Therefore, $2y^2dy=x^3dx$
$\int 2y^2dy=\int x^3dx$
Or, $\frac{2y^3}{3}=\frac{x^4}{4}+C'$
Multiplying both sides by 12 and taking $C=12C'$.
$$8y^3=3x^4+C$$

Published by
Brooks Cole

ISBN 10:
1-28505-709-0

ISBN 13:
978-1-28505-709-5

$8y^3=3x^4+C$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.