Answer
$$\frac{1}{2}{y^2} = - 2{x^2} + C$$
Work Step by Step
$$\eqalign{
& \frac{{dy}}{{dx}} = - \frac{{4x}}{y} \cr
& {\text{Separate the variables}} \cr
& ydy = - 4xdx \cr
& {\text{Integrate both sides}} \cr
& \int {ydy} = - \int {4xdx} \cr
& \frac{1}{2}{y^2} = - 2{x^2} + C \cr
& \cr
& {\text{Graph}} \cr} $$
