Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises - Page 158: 74

Answer

$y'' = 2[(\cos x)^{2} - (\sin x)^{2}]$

Work Step by Step

$y = (\sin x)^{2} $ $y' = 2(\sin x)(\cos x)$ $y'' = [2(\cos x)] (\cos x) + [2(\sin x)](-\sin x)$ $y'' = 2(\cos x)^{2} - 2(\sin x)^{2}$ $y'' = 2[(\cos x)^{2} - (\sin x)^{2}]$
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