Answer
$y'' = 2[(\cos x)^{2} - (\sin x)^{2}]$
Work Step by Step
$y = (\sin x)^{2} $
$y' = 2(\sin x)(\cos x)$
$y'' = [2(\cos x)] (\cos x) + [2(\sin x)](-\sin x)$
$y'' = 2(\cos x)^{2} - 2(\sin x)^{2}$
$y'' = 2[(\cos x)^{2} - (\sin x)^{2}]$
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