Answer
$y' = 2(sin(2x) - 2cos(x)sin(x))$
Work Step by Step
$y = 1-cos(2x) + 2(cos(x))^{2}$
$y' = -(-sin(2x))(2) + (2 \times 2)cos(x)(-sin(x))$
$y' = 2sin(2x)-4cos(x)sin(x)$
$y' = 2(sin(2x) - 2cos(x)sin(x))$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - Review Exercises - Page 158: 58
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