Answer
$h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{-x^{2} -10x + 3}{(x^{2} + 3)^{2}})$
Work Step by Step
$h(x) = (\frac{(x+5)}{(x^{2}+3)})^{2}$
$h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{[1(x^{2} + 3)] - [(2x)(x+5)]}{(x^{2} + 3)^{2}})$
$h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{x^{2} + 3 - 2x^{2} -10x}{(x^{2} + 3)^{2}})$
$h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{-x^{2} -10x + 3}{(x^{2} + 3)^{2}})$