Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises - Page 158: 64

Answer

$h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{-x^{2} -10x + 3}{(x^{2} + 3)^{2}})$

Work Step by Step

$h(x) = (\frac{(x+5)}{(x^{2}+3)})^{2}$ $h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{[1(x^{2} + 3)] - [(2x)(x+5)]}{(x^{2} + 3)^{2}})$ $h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{x^{2} + 3 - 2x^{2} -10x}{(x^{2} + 3)^{2}})$ $h'(x) = 2(\frac{(x+5)}{(x^{2}+3)})(\frac{-x^{2} -10x + 3}{(x^{2} + 3)^{2}})$
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