Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises - Page 158: 72

Answer

$y'' = \frac{50}{(5x+1)^{3}}$

Work Step by Step

$y = \frac{1}{(5x+1)}$ $y = (5x+1)^{-1}$ $y' = (-1)(5x+1)^{-2}(5)$ $y' = (-5)(5x+1)^{-2}$ $y'' = ((-5) \times (-2))(5x+1)^{-3}(5)$ $y'' = 10(5x+1)^{-3}(5)$ $y'' = 50(5x+1)^{-3}$ $y'' = \frac{50}{(5x+1)^{3}}$
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