Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises - Page 158: 56

Answer

$f(x) = \frac{1}{(5x+1^{2}$}$ $f'(x) = \frac{-10}{(5x+1)^{3}}$

Work Step by Step

$f(x) = \frac{1}{(5x+1^{2}$}$ $f(x) = (5x+1)^{-2}$ $f'(x) = (-2)(5x+1)^{(-2-1)}(5)$ $f'(x) = -10(5x+1)^{-3}$ $f'(x) = \frac{-10}{(5x+1)^{3}}$
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