Answer
$f(x) = \frac{1}{(5x+1^{2}$}$
$f'(x) = \frac{-10}{(5x+1)^{3}}$
Work Step by Step
$f(x) = \frac{1}{(5x+1^{2}$}$
$f(x) = (5x+1)^{-2}$
$f'(x) = (-2)(5x+1)^{(-2-1)}(5)$
$f'(x) = -10(5x+1)^{-3}$
$f'(x) = \frac{-10}{(5x+1)^{3}}$
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