Answer
$\frac{1}{2}$
Work Step by Step
a) Find the parametrization of the function.
1. x(t) = t
2. y(t) = 0
3. 0 $\leq$ t $\leq$ 1
4. x'(t) = 1
5. y'(t) = 0
6. p(x,y) = x(t) = t
b) Integrate.
$\int(t*\sqrt (1^{2}+0^{2}))dt$ from t = 0 to t= 1
$= [\frac{1}{2}t^{2}]$ from t = 0 to t = 1
$= \frac{1}{2}$
