Answer
TRUE.
Work Step by Step
$F(x,y) = -y^2 j$ when $(x,y)$ is on the positive Y-axis. Since $-y^2<0$, the vector points in the negative Y-direction. Thus the statement is $ \fbox{true}$.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 15 - Vector Analysis - 15.1 Exercises - Page 1050: 80
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