Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 15 - Vector Analysis - 15.1 Exercises - Page 1050: 64

Answer

$\frac{11}{6}$

Work Step by Step

div $\textbf{F}=\nabla\cdot \textbf{F}=\nabla\cdot\langle\ln(xyz),\ln(xyz),\ln(xyz)\rangle$ $=\frac{\partial}{\partial x}(\ln(xyz))+\frac{\partial}{\partial y}(\ln(xyz))+\frac{\partial}{\partial z}(\ln(xyz))$ $=\frac{1}{x}+\frac{1}{y}+\frac{1}{z}$ Knowing that $(x,y,z)=(3,2,1)$, We get div $\textbf{F}=\frac{1}{3}+\frac{1}{2}+\frac{1}{1}=\frac{11}{6}$
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