Answer
\[\begin{align}
& \left( \mathbf{a} \right)11\mathbf{i}+\mathbf{j}-2\mathbf{k} \\
& \left( \mathbf{b} \right)-11\mathbf{i}-\mathbf{j}+2\mathbf{k} \\
& \left( \mathbf{c} \right)\mathbf{0} \\
\end{align}\]
Work Step by Step
\[\begin{align}
& \text{Let }\mathbf{u}=\left\langle 0,2,1 \right\rangle ,\text{ }\mathbf{v}=\left\langle 1,-3,4 \right\rangle \\
& \\
& \left( \mathbf{a} \right)\text{Find }\mathbf{u}\times \mathbf{v} \\
& \mathbf{u}\times \mathbf{v}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
0 & 2 & 1 \\
1 & -3 & 4 \\
\end{matrix} \right| \\
& \mathbf{u}\times \mathbf{v}=\left| \begin{matrix}
2 & 1 \\
-3 & 4 \\
\end{matrix} \right|\mathbf{i}-\left| \begin{matrix}
0 & 1 \\
1 & 4 \\
\end{matrix} \right|\mathbf{j}+\left| \begin{matrix}
0 & 2 \\
1 & -3 \\
\end{matrix} \right|\mathbf{k} \\
& \mathbf{u}\times \mathbf{v}=11\mathbf{i}+\mathbf{j}-2\mathbf{k} \\
& \\
& \left( \mathbf{b} \right)\text{Find }\mathbf{v}\times \mathbf{u} \\
& \mathbf{v}\times \mathbf{u}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
1 & -3 & 4 \\
0 & 2 & 1 \\
\end{matrix} \right| \\
& \mathbf{v}\times \mathbf{u}=\left| \begin{matrix}
-3 & 4 \\
2 & 1 \\
\end{matrix} \right|\mathbf{i}-\left| \begin{matrix}
1 & 4 \\
0 & 1 \\
\end{matrix} \right|\mathbf{j}+\left| \begin{matrix}
1 & -3 \\
0 & 2 \\
\end{matrix} \right|\mathbf{k} \\
& \mathbf{v}\times \mathbf{u}=-11\mathbf{i}-\mathbf{j}+2\mathbf{k} \\
& \\
& \left( \mathbf{c} \right)\text{Find }\mathbf{v}\times \mathbf{v} \\
& \mathbf{v}\times \mathbf{v}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
1 & -3 & 4 \\
1 & -3 & 4 \\
\end{matrix} \right| \\
& \mathbf{v}\times \mathbf{v}=\mathbf{0} \\
\end{align}\]