Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - Review Exercises - Page 811: 3

Answer

$${\bf{v}} = 4{\bf{i}} + 4\sqrt 3 {\bf{j}}$$

Work Step by Step

$$\eqalign{ & \left\| {\bf{v}} \right\| = 8,{\text{ }}\theta = 60^\circ \cr & {\text{The components of }}{\bf{v}}{\text{ are given by }} \cr & {\bf{v}} = \left\| {\bf{v}} \right\|\left( {\cos \theta {\bf{i}} + \sin \theta {\bf{j}}} \right) \cr & {\text{Then,}} \cr & {\bf{v}} = 8\left( {\cos 60^\circ {\bf{i}} + \sin 60^\circ {\bf{j}}} \right) \cr & {\text{Simplifying}} \cr & {\bf{v}} = 8\left( {\frac{1}{2}{\bf{i}} + \frac{{\sqrt 3 }}{2}{\bf{j}}} \right) \cr & {\bf{v}} = 4{\bf{i}} + 4\sqrt 3 {\bf{j}} \cr} $$
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