Answer
\[\begin{align}
& \left( \mathbf{a} \right)-8\mathbf{i}-10\mathbf{j}+6\mathbf{k} \\
& \left( \mathbf{b} \right)8\mathbf{i}+10\mathbf{j}-6\mathbf{k} \\
& \left( \mathbf{c} \right)\mathbf{0} \\
\end{align}\]
Work Step by Step
\[\begin{align}
& \text{Let }\mathbf{u}=\left\langle 2,-4,-4 \right\rangle ,\text{ }\mathbf{v}=\left\langle 1,1,3 \right\rangle \\
& \\
& \left( \mathbf{a} \right)\text{Find }\mathbf{u}\times \mathbf{v} \\
& \mathbf{u}\times \mathbf{v}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
2 & -4 & -4 \\
1 & 1 & 3 \\
\end{matrix} \right| \\
& \mathbf{u}\times \mathbf{v}=\left| \begin{matrix}
-4 & -4 \\
1 & 3 \\
\end{matrix} \right|\mathbf{i}-\left| \begin{matrix}
2 & -4 \\
1 & 3 \\
\end{matrix} \right|\mathbf{j}+\left| \begin{matrix}
2 & -4 \\
1 & 1 \\
\end{matrix} \right|\mathbf{k} \\
& \mathbf{u}\times \mathbf{v}=-8\mathbf{i}-10\mathbf{j}+6\mathbf{k} \\
& \\
& \left( \mathbf{b} \right)\text{Find }\mathbf{v}\times \mathbf{u} \\
& \mathbf{v}\times \mathbf{u}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
1 & 1 & 3 \\
2 & -4 & -4 \\
\end{matrix} \right| \\
& \mathbf{v}\times \mathbf{u}=\left| \begin{matrix}
1 & 3 \\
-4 & -4 \\
\end{matrix} \right|\mathbf{i}-\left| \begin{matrix}
1 & 3 \\
2 & -4 \\
\end{matrix} \right|\mathbf{j}+\left| \begin{matrix}
1 & 1 \\
2 & -4 \\
\end{matrix} \right|\mathbf{k} \\
& \mathbf{v}\times \mathbf{u}=8\mathbf{i}+10\mathbf{j}-6\mathbf{k} \\
& \\
& \left( \mathbf{c} \right)\text{Find }\mathbf{v}\times \mathbf{v} \\
& \mathbf{v}\times \mathbf{v}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
1 & 1 & 3 \\
1 & 1 & 3 \\
\end{matrix} \right| \\
& \mathbf{v}\times \mathbf{v}=\mathbf{0} \\
\end{align}\]