Answer
\[\begin{align}
& \left( \mathbf{a} \right)-9\mathbf{i}+26\mathbf{j}-7\mathbf{k} \\
& \left( \mathbf{b} \right)9\mathbf{i}-26\mathbf{j}+7\mathbf{k} \\
& \left( \mathbf{c} \right)\mathbf{0} \\
\end{align}\]
Work Step by Step
\[\begin{align}
& \text{Let }\mathbf{u}=4\mathbf{i}+3\mathbf{j}+6\mathbf{k},\text{ }\mathbf{v}=5\mathbf{i}+2\mathbf{j}+\mathbf{k} \\
& \\
& \left( \mathbf{a} \right)\text{Find }\mathbf{u}\times \mathbf{v} \\
& \mathbf{u}\times \mathbf{v}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
4 & 3 & 6 \\
5 & 2 & 1 \\
\end{matrix} \right| \\
& \mathbf{u}\times \mathbf{v}=\left| \begin{matrix}
3 & 6 \\
2 & 1 \\
\end{matrix} \right|\mathbf{i}-\left| \begin{matrix}
4 & 6 \\
5 & 1 \\
\end{matrix} \right|\mathbf{j}+\left| \begin{matrix}
4 & 3 \\
5 & 2 \\
\end{matrix} \right|\mathbf{k} \\
& \mathbf{u}\times \mathbf{v}=-9\mathbf{i}+26\mathbf{j}-7\mathbf{k} \\
& \\
& \left( \mathbf{b} \right)\text{Find }\mathbf{v}\times \mathbf{u} \\
& \mathbf{v}\times \mathbf{u}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
5 & 2 & 1 \\
4 & 3 & 6 \\
\end{matrix} \right| \\
& \mathbf{v}\times \mathbf{u}=\left| \begin{matrix}
2 & 1 \\
3 & 6 \\
\end{matrix} \right|\mathbf{i}-\left| \begin{matrix}
5 & 1 \\
4 & 6 \\
\end{matrix} \right|\mathbf{j}+\left| \begin{matrix}
5 & 2 \\
4 & 3 \\
\end{matrix} \right|\mathbf{k} \\
& \mathbf{v}\times \mathbf{u}=9\mathbf{i}-26\mathbf{j}+7\mathbf{k} \\
& \\
& \left( \mathbf{c} \right)\text{Find }\mathbf{v}\times \mathbf{v} \\
& \mathbf{v}\times \mathbf{v}=\left| \begin{matrix}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
5 & 2 & 1 \\
5 & 2 & 1 \\
\end{matrix} \right| \\
& \mathbf{v}\times \mathbf{v}=\left| \begin{matrix}
2 & 1 \\
2 & 1 \\
\end{matrix} \right|\mathbf{i}-\left| \begin{matrix}
5 & 1 \\
5 & 1 \\
\end{matrix} \right|\mathbf{j}+\left| \begin{matrix}
5 & 2 \\
5 & 2 \\
\end{matrix} \right|\mathbf{k} \\
& \mathbf{v}\times \mathbf{v}=\mathbf{0} \\
\end{align}\]