Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - Review Exercises - Page 811: 27

Answer

$${\bf{w}} = \left\langle {2,10} \right\rangle $$

Work Step by Step

$$\eqalign{ & {\text{Let }}{\bf{u}} = \left\langle {7,9} \right\rangle ,{\text{ }}{\bf{v}} = \left\langle {1,5} \right\rangle \cr & {\text{Let }}{\bf{w}} = {\text{pro}}{{\text{j}}_{\bf{v}}}{\bf{u}} = \left( {\frac{{{\bf{u}} \cdot {\bf{v}}}}{{{{\left\| {\bf{v}} \right\|}^2}}}} \right){\bf{v}} \cr & {\bf{w}} = \left( {\frac{{\left\langle {7,9} \right\rangle \cdot \left\langle {1,5} \right\rangle }}{{{{\left\| {\left\langle {1,5} \right\rangle } \right\|}^2}}}} \right)\left\langle {1,5} \right\rangle \cr & {\bf{w}} = \left( {\frac{{7 + 45}}{{1 + 25}}} \right)\left\langle {1,5} \right\rangle \cr & {\bf{w}} = 2\left\langle {1,5} \right\rangle \cr & {\bf{w}} = \left\langle {2,10} \right\rangle \cr} $$
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