Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - 10.3 Exercises - Page 711: 1

$\frac{dy}{dx} = \frac{-3}{t}$

1. Calculate $\frac{dy}{dt}$: $y = 7 - 6t$ $dy =( 0 - 6*(1) )$ $\frac{dy}{dt} = -6$ 2. Calculate $\frac{dx}{dt}$: $x = t^2$ $dx = (2t)dt$ $\frac{dx}{dt} = 2t$ 3. Using the expression: $\frac{dy}{dx} = \frac{dy/dt}{dx/dt}$, find the derivate: $\frac{dy}{dx} = \frac{-6}{2t} = \frac{-3}{t}$