Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 9 - Infinite Series - 9.5 The Comparison, Ratio, And Root Tests - Exercises Set 9.5 - Page 637: 36

Answer

Converges

Work Step by Step

We can see that $\Sigma_{k=1}^{\infty} \dfrac{4+|cos x|}{k^3} \lt \Sigma_{k=1}^{\infty} \dfrac{6}{k^3}$ But the series $\Sigma_{k=1}^{\infty} \dfrac{6}{k^3}$ is a p-series with $p=3$, so it converges by the p-series. This implies that the given series is less than a converging series, so it converges.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.