Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 9 - Infinite Series - 9.3 Infinite Series - Exercises Set 9.3 - Page 621: 6

Answer

Divergent

Work Step by Step

Given $$ \sum_{k=1}^{\infty} \left(\frac{-3}{2}\right)^{k+1}$$ This is a geometric series with $|r|=\frac{3}{2}>1$ , so $\displaystyle \sum_{k=1}^{\infty} \left(\frac{-3}{2}\right)^{k+1}$ is a divergent series
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