Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 9 - Infinite Series - 9.3 Infinite Series - Exercises Set 9.3 - Page 621: 14

Answer

The series diverges.

Work Step by Step

The series can be rewritten as $\mathop \sum \limits_{k = 1}^\infty {5^{3k}}\cdot{7^{1 - k}} = \mathop \sum \limits_{k = 1}^\infty {\left( {{5^3}} \right)^k}\cdot\frac{7}{{{7^k}}} = \mathop \sum \limits_{k = 1}^\infty 7{\left( {\frac{{{5^3}}}{7}} \right)^k}$ This is a geometric series with $r = \frac{{{5^3}}}{7}$. Since $\left| r \right| = \frac{{{5^3}}}{7} > 1$, the series diverges.
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