Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.7 Rectilinear Motion Revisited Using Integration - Exercises Set 4.7 - Page 329: 4

Answer

36 ft

Work Step by Step

Free fall model: \[ \begin{array}{l} v(t)=-g t+v_{0} \\ s(t)=v_{0} t-\frac{1}{2} g t^{2}+s_{0} \end{array} \] \[ 48=-32 t+0 \] Thus $t=\frac{3}{2}$ $g=32$, $v_{0}=0$ and $v(t)=48$ in the velocity formula \[ 0=-\frac{1}{2} \cdot 1.5^{2} \cdot 32+s_{0} \] In the position formula $s_{0}=36$ $s(t)=0, t=1.5, v_{0}=0$, $v(t)=48$ and $g=32$
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