Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.3 Integration By Substitution - Exercises Set 4.3: 14

Answer

$3\sin \frac{x}{3}+C$

Work Step by Step

Use the substitution $u=\frac{u}{3}$. Then $dx=\frac{du}{3}$, so $du=3dx$. $\int\cos \frac{x}{3} dx$ $=\int\cos u*3du$ $=\int3\cos udu$ $=3\sin u+C$ $=3\sin \frac{x}{3}+C$
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