Answer
$3\sin \frac{x}{3}+C$
Work Step by Step
Use the substitution $u=\frac{u}{3}$. Then $dx=\frac{du}{3}$, so $du=3dx$.
$\int\cos \frac{x}{3} dx$
$=\int\cos u*3du$
$=\int3\cos udu$
$=3\sin u+C$
$=3\sin \frac{x}{3}+C$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 4 - Integration - 4.3 Integration By Substitution - Exercises Set 4.3 - Page 286: 14
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