Answer
$-\frac{1}{7}\cos 7x+C$
Work Step by Step
Use the substitution $u=7x$. Then $du=7dx$, so $dx=\frac{1}{7}du$.
$\int\sin 7x dx$
$=\int\sin u*\frac{1}{7}du$
$=\int\frac{1}{7}\sin u du$
$=-\frac{1}{7}\cos u+C$
$=-\frac{1}{7}\cos 7x+C$
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