Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.3 Integration By Substitution - Exercises Set 4.3 - Page 286: 13


$-\frac{1}{7}\cos 7x+C$

Work Step by Step

Use the substitution $u=7x$. Then $du=7dx$, so $dx=\frac{1}{7}du$. $\int\sin 7x dx$ $=\int\sin u*\frac{1}{7}du$ $=\int\frac{1}{7}\sin u du$ $=-\frac{1}{7}\cos u+C$ $=-\frac{1}{7}\cos 7x+C$
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