Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 12 - Vector-Valued Functions - Chapter 12 Review Exercises - Page 903: 26

Answer

$\frac{\sqrt{2}}{3}$

Work Step by Step

See Theorem $12.5 .2 b$ \[ \begin{array}{l} \kappa(t)=\frac{\left\|\mathrm{r}^{\prime}(t) \times \mathrm{r}^{\prime \prime}(t)\right\|}{\left\|\mathrm{r}^{\prime}(t)\right\|^{3}} =\qquad \kappa(0)\\ \begin{array}{l} \mathrm{r}^{\prime}(t)=\left\langle 2,2 \mathrm{e}^{2 t},-2 e^{-2 t}\right\rangle, \quad \mathrm{r}^{\prime}(0)=\{2,2,-2\rangle \\ \mathrm{r}^{\prime \prime}(t)=\left\langle 0,4 c^{2 t}, 4 c^{-2 t}\right\rangle, \quad \mathrm{r}^{\prime \prime}(0)=\langle 0,4,4\rangle \\ \mathrm{r}^{\prime}(0) \times \mathrm{r}^{\prime \prime}(0)=\left|\begin{array}{ccc} i & j & k \\ 2 & 2 & -2 \\ 0 & 4 & 4 \end{array}\right|=(8+8) \mathrm{i}-8 j+8 \mathrm{k} \\ \frac{\|\langle 16,-8,8\rangle\|}{(12)^{3 / 2}}=\frac{8 \sqrt{6}}{12 \sqrt{12}}=\frac{\sqrt{2}}{3}=\kappa(0) \end{array} \end{array} \]
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