Answer
Ans. K=2, 5
Work Step by Step
Given:- $p(x)=k^2x^3-7kx+10$ and x-1 is the factor of p(x)
Therefore put x=1 , p(x)=0
We get $k^2-7k+10=0$
$k^2-5k-2k+10=0$
$(k-2) (k-5)$
K=2, 5
Ans.
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Appendix C - Solving Polynomial Equations - Exercise Set C - Page A33: 23
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