Answer
The limit is $\frac{\pi}{2}.$
Work Step by Step
No issues arise if we evaluate the function at the given point, so the limit approaches $\frac{\pi}{2} \sin{(\pi - \pi/2)} = \frac{\pi}{2} \sin{\frac{\pi}{2}} = \frac{\pi}{2}$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 14 - Section 14.2 - Limits and Continuity - 14.2 Exercise - Page 960: 9
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