Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.2 - Series - 11.2 Exercises - Page 748: 15

Answer

a) Converges b) Diverges

Work Step by Step

a) $\lim\limits_{n \to \infty}$$ a_{n}$ =$\lim\limits_{n \to \infty}$ $\frac{2n}{3n+1}$= $\frac{2}{3}$ since the limit of the sequence $ a_{n}$ exists the sequence converges. b) Since $\lim\limits_{n \to \infty}$$ a_{n}$ =$\frac{2}{3}$ $\ne$ 0 the series$\sum_{n=1}^\infty$$ a_{n}$ is divergent by the Test for Divergence.
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