Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.2 - Series - 11.2 Exercises - Page 748: 14

Answer

The series is convergent. $\sum_{n=1}^{\infty}\frac{7^{n+1}}{10^n}=\frac{49}{3}$

Work Step by Step

The graph of the sequence of terms and the sequence of partial sums is given below. From the graph, as $n$ becomes larger the value of $S_n$ approaches to a single value. It appears that the series is convergent. The series $\sum_{n=1}^\infty\frac{7^{n+1}}{10^n}$ is an infinite geometric series with the first term $a_1=\frac{49}{10}$ and the common ratio $r=\frac{7}{10}$. Find the sum of the series: $\sum_{n=1}^{\infty}\frac{7^{n+1}}{10^n}=\frac{a_1}{1-r}=\frac{49/10}{1-7/10}=\frac{49/10}{3/10}=\frac{49}{3}$
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