Answer
$0,7,26,63,124$
Work Step by Step
$a_{n}=n^{3}-1$
Substitute $1,2,3,4,5$ to $n$:
$a_{1}=1^{3}-1=0$
$a_{2}=2^{3}-1=8-1=7$
$a_{3}=3^{3}-1=27-1=26$
$a_{4}=4^{3}-1=64-1=63$
$a_{5}=5^{3}-1=125-1=124$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises - Page 735: 3
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