Answer
$1,3,7,15,31$
Work Step by Step
Given that $a_{1}=1$ and $a_{n+1}=2a_{n}+1$
substitute $1,2,3,4$ to $n$:
$a_{2}=2a_{1}+1=2(1)+1=3$
$a_{3}=2a_{2}+1=2(3)+1=7$
$a_{4}=2a_{3}+1=2(7)+1=15$
$a_{5}=2a_{4}+1=2(15)+1=31$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises - Page 735: 13
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