Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises - Page 735: 23

Answer

$0.4286, 0.4615, 0.4737, 0.4800, 0.4839, 0.4865, 0.4884, 0.4898, 0.4909, 0.4918$ $\lim\limits_{n \to \infty}a_n=0.5$

Work Step by Step

It is given a sequence formulated by $a_n=\frac{3n}{1+6n}$ Substituting $n=1,2,\ldots,10$, we get the first ten terms of the sequence: $0.4286, 0.4615, 0.4737, 0.4800, 0.4839, 0.4865, 0.4884, 0.4898, 0.4909, 0.4918$ Using these terms, the sequence appears to have a limit. Calculate the limit: $\lim\limits_{n \to \infty}a_n=\lim\limits_{n \to \infty}\frac{3n}{1+6n}$ $=\lim\limits_{n \to \infty}\frac{3}{\frac{1}{n}+6}$ $=\frac{3}{0+6}$ $=0.5$ So, the sequence converges to $0.5$
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