Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 40

Answer

$$1.74 \times 10^{15} . $$

Work Step by Step

We have $$\frac{1}{(24 \times 10^{-9})^{2}}=0.00174\times 10^{18}=1.74 \times 10^{15} . $$
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