Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 34


$$18.2\times 10^{-15}. $$

Work Step by Step

We have $$\frac{ 1}{55\times 10^{12}}=0.01818\times 10^{-12}=18.2\times 10^{-15}. $$
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