Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 35

Answer

$$123 \times 10^{21}. $$

Work Step by Step

We have $$(350\times 10^{9})^2=122500 \times 10^{18}=123 \times 10^{21}. $$
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