Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 30


$$8.82\times 10^{-18}.$$

Work Step by Step

By subtracting the exponents and dividing the like terms, we have $$\frac{ 450\times 10^{-12} }{51\times 10^{6}}=\frac{ 450}{51} \times 10^{-12-6} \\ =8.82\times 10^{-18}.$$
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