Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 29


$$588\times 10^{12}.$$

Work Step by Step

By subtracting the exponents and dividing the like terms, we have $$\frac{ 70.5\times 10^6 }{120\times 10^{-9}}=\frac{ 70.5}{120} \times 10^{6-(-9)} \\ =0.588\times 10^{15} =588\times 10^{12}.$$
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