## Elementary Technical Mathematics

10$\frac{13}{16}$ in,3$\frac{3}{4}$ in
Let the length of the diameter of each three circles =3$\frac{5}{16}$ in the length of the each four blank spaces = $\frac{7}{32}$ in to find the length of the steel strip we will add the entire dimensions = $\frac{7}{32}$ in + 3$\frac{5}{16}$ in+ $\frac{7}{32}$ in+ 3$\frac{5}{16}$ in+$\frac{7}{32}$ in+ 3$\frac{5}{16}$ in+$\frac{7}{32}$ in =$4 \times$ $\frac{7}{32}$ + $3 \times$ $\frac{53}{16}$ =$\frac{14}{16}$ + $\frac{159}{16}$ = $\frac{173}{16}$ =10$\frac{13}{16}$ in Width of the stell strip = $\frac{7}{32}$ in + 3$\frac{5}{16}$ in+ $\frac{7}{32}$ in =$2 \times$ $\frac{7}{32}$ + $\frac{53}{16}$ =$\frac{7}{16}$ + $\frac{53}{16}$ =$\frac{60}{16}$ =$\frac{15}{4}$ =3$\frac{3}{4}$ in