Answer
10$\frac{13}{16}$ in,3$\frac{3}{4}$ in
Work Step by Step
Let the length of the diameter of each three circles =3$\frac{5}{16}$ in
the length of the each four blank spaces = $\frac{7}{32}$ in
to find the length of the steel strip we will add the entire dimensions =
$\frac{7}{32}$ in + 3$\frac{5}{16}$ in+ $\frac{7}{32}$ in+ 3$\frac{5}{16}$ in+$\frac{7}{32}$ in+ 3$\frac{5}{16}$ in+$\frac{7}{32}$ in
=$4 \times$ $\frac{7}{32}$ + $3 \times$ $\frac{53}{16}$
=$\frac{14}{16}$ + $\frac{159}{16}$
= $\frac{173}{16}$
=10$\frac{13}{16}$ in
Width of the stell strip = $\frac{7}{32}$ in + 3$\frac{5}{16}$ in+ $\frac{7}{32}$ in
=$2 \times$ $\frac{7}{32}$ + $\frac{53}{16}$
=$\frac{7}{16}$ + $\frac{53}{16}$
=$\frac{60}{16}$
=$\frac{15}{4}$
=3$\frac{3}{4}$ in
