Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 42: 81


10$\frac{13}{16}$ in,3$\frac{3}{4}$ in

Work Step by Step

Let the length of the diameter of each three circles =3$\frac{5}{16}$ in the length of the each four blank spaces = $\frac{7}{32}$ in to find the length of the steel strip we will add the entire dimensions = $\frac{7}{32}$ in + 3$\frac{5}{16}$ in+ $\frac{7}{32}$ in+ 3$\frac{5}{16}$ in+$\frac{7}{32}$ in+ 3$\frac{5}{16}$ in+$\frac{7}{32}$ in =$4 \times$ $\frac{7}{32}$ + $3 \times$ $\frac{53}{16}$ =$\frac{14}{16}$ + $\frac{159}{16}$ = $\frac{173}{16}$ =10$\frac{13}{16}$ in Width of the stell strip = $\frac{7}{32}$ in + 3$\frac{5}{16}$ in+ $\frac{7}{32}$ in =$2 \times$ $\frac{7}{32}$ + $\frac{53}{16}$ =$\frac{7}{16}$ + $\frac{53}{16}$ =$\frac{60}{16}$ =$\frac{15}{4}$ =3$\frac{3}{4}$ in
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.