## Elementary Technical Mathematics

$\frac{5}{64}$ in
Lets consider the diameter of the shaft is $\frac{7}{8}$ in We have to find the length that must be reduced so that the diameter of the shaft is $\frac{51}{64}$ in. Therefore length = $\frac{7}{8}$ in - $\frac{51}{64}$ in. = $\frac{7}{8}\times$ $\frac{8}{8}$ - $\frac{51}{64}$ = $\frac{56}{64}$ - $\frac{51}{64}$ =$\frac{5}{64}$ in