Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise: 77

Answer

$\frac{5}{64}$ in

Work Step by Step

Lets consider the diameter of the shaft is $\frac{7}{8}$ in We have to find the length that must be reduced so that the diameter of the shaft is $\frac{51}{64}$ in. Therefore length = $\frac{7}{8}$ in - $\frac{51}{64}$ in. = $\frac{7}{8}\times$ $\frac{8}{8}$ - $\frac{51}{64}$ = $\frac{56}{64}$ - $\frac{51}{64}$ =$\frac{5}{64}$ in
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