## Elementary Technical Mathematics

16$\frac{1}{2}$ ft
Lets consider the house built on 65 $\frac{3}{4}$ ft wide lot The house is 5$\frac{5}{12}$ ft wide from one side of the lot and is 43 $\frac{5}{6}$ ft wide Distance from the other side of the lot = 65 $\frac{3}{4}$ ft - 5$\frac{5}{12}$ ft - 43 $\frac{5}{6}$ ft =$\frac{263}{4}$ - $\frac{65}{12}$ - $\frac{263}{6}$ =$\frac{263}{4}\times$ $\frac{3}{3}$ -$\frac{65}{12}$ -$\frac{263}{6}\times$ $\frac{2}{2}$ =$\frac{789}{12}$ - $\frac{65}{12}$ - $\frac{526}{12}$ =$\frac{198}{12}$ =$\frac{33}{2}$ =16$\frac{1}{2}$ ft