Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise: 76

Answer

$\frac{5}{16}$ in

Work Step by Step

Lets consider the formiula for tap drill size , TDS = OD – P, where OD is the outside diameter and P is the pitch Given outside diameter is $\frac{3}{8}$ in and pitch = $\frac{1}{16}$ in So TDS = $\frac{3}{8}$ - $\frac{1}{16}$ =$\frac{3}{8}\times$ $\frac{2}{2}$ - $\frac{1}{16}$ =$\frac{6}{16}$ - $\frac{1}{16}$ = $\frac{5}{16}$ in
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