#### Answer

12$\frac{1}{16}$ in

#### Work Step by Step

Let the three distances between two holes are 3$\frac{3}{8}$ in, 5$\frac{5}{16}$ in and 3$\frac{3}{8}$ in
total distance between the centers of the two end holes of the plate = 3$\frac{3}{8}$ in + 5$\frac{5}{16}$ in + 3$\frac{3}{8}$ in
=$\frac{27}{8}$ + $\frac{85}{16}$ + $\frac{27}{8}$
=$\frac{54}{8}$ + $\frac{85}{16}$
=$\frac{54}{8}\times$ $\frac{2}{2}$ + $\frac{85}{16}$
= $\frac{108}{16}$ + $\frac{85}{16}$
= $\frac{193}{16}$
= 12$\frac{1}{16}$ in