## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 41: 70

#### Answer

12$\frac{1}{16}$ in

#### Work Step by Step

Let the three distances between two holes are 3$\frac{3}{8}$ in, 5$\frac{5}{16}$ in and 3$\frac{3}{8}$ in total distance between the centers of the two end holes of the plate = 3$\frac{3}{8}$ in + 5$\frac{5}{16}$ in + 3$\frac{3}{8}$ in =$\frac{27}{8}$ + $\frac{85}{16}$ + $\frac{27}{8}$ =$\frac{54}{8}$ + $\frac{85}{16}$ =$\frac{54}{8}\times$ $\frac{2}{2}$ + $\frac{85}{16}$ = $\frac{108}{16}$ + $\frac{85}{16}$ = $\frac{193}{16}$ = 12$\frac{1}{16}$ in

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