## Elementary Technical Mathematics

5$\frac{13}{16}$ A
Let the five currents are 1$\frac{1}{2}$ A , $\frac{3}{4}$ A ,$\frac{3}{16}$ A,$\frac{7}{8}$ A, and 2$\frac{1}{2}$A total current = 1$\frac{1}{2}$ A+ $\frac{3}{4}$ A + $\frac{3}{16}$ A+$\frac{7}{8}$ A+ 2$\frac{1}{2}$A = $\frac{3}{2}$ + $\frac{3}{4}$ + $\frac{3}{16}$ + $\frac{7}{8}$A + $\frac{5}{2}$A =$\frac{8}{2}\times$ $\frac{8}{8}$ + $\frac{3}{4} \times$ $\frac{4}{4}$ + $\frac{3}{16}$ +$\frac{7}{8} \times$ $\frac{2}{2}$ =$\frac{64}{16}$ + $\frac{12}{16}$ `+ $\frac{3}{16}$ + $\frac{14}{16}$ =$\frac{93}{16}$ =5$\frac{13}{16}$ A