## Elementary Technical Mathematics

3$\frac{1}{4}$ A
Let the two currents are 1$\frac{3}{4}$ A and 1$\frac{1}{2}$A total current = 1$\frac{3}{4}$ + 1$\frac{1}{2}$ = $\frac{7}{4}$ + $\frac{3}{2}$ =$\frac{7}{4}$ + $\frac{3}{2} \times$ $\frac{2}{2}$ =$\frac{7}{4}$ + $\frac{6}{4}$ ` =$\frac{13}{4}$ =3$\frac{1}{4}$ A