Answer
2$\frac{7}{16}$ A
Work Step by Step
Let the three currents are 2$\frac{1}{4}$ A , $\frac{1}{8}$ A and $\frac{1}{16}$A
total current = 2$\frac{1}{4}$ A+ $\frac{1}{8}$ A + $\frac{1}{16}$A
= $\frac{9}{4}$ + $\frac{1}{8}$ + $\frac{1}{16}$
=$\frac{9}{4}\times$ $\frac{4}{4}$ + $ \frac{1}{8} \times$ $\frac{2}{2}$ +$\frac{1}{16}$
=$\frac{36}{16}$ + $\frac{2}{16}$ `+ $\frac{1}{16}$
=$\frac{39}{16}$
=2$\frac{7}{16}$ A
