## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise - Page 41: 64

#### Answer

21$\frac{27}{32}$ in

#### Work Step by Step

Let perimeter of the triangle is 59$\frac{9}{32}$ in , the length of one side is 19$\frac{5}{8}$in and length of second side is 17$\frac{13}{16}$ in therefore the length of the third side = Perimeter – length of one side – length of seond side = 59$\frac{9}{32}$ - 19$\frac{5}{8}$ - 17$\frac{13}{16}$ =$\frac{1897}{32}$ - $\frac{157}{8}$ - $\frac{285}{16}$ = $\frac{1897}{32}$ - $\frac{157}{8} \times$ $\frac{4}{4}$ - $\frac{285}{16} \times$ $\frac{2}{2}$ =$\frac{1897}{32}$ - $\frac{628}{32}$ - $\frac{570}{32}$ $\frac{699}{32}$ =21$\frac{27}{32}$ in

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