Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.7 - Addition and Subtraction of Fractions - Exercise: 48

Answer

$12\frac{15}{16} \text{ft}$

Work Step by Step

Add the given lengths to find the total length of the welded piece:. Total length $=3\frac{1}{4} + 2\frac{3}{8} + 3\frac{1}{8} + 4\frac{3}{16} \\=(3+2+3+4) + (\frac{1}{4}+\frac{3}{8}+\frac{1}{8} + \frac{3}{16}) \\=12+ (\frac{1}{4}+\frac{4}{8}+\frac{3}{16})$ Make the fractions similar using their LCD of $16$ to obtain: Total length $\\=12+(\frac{4}{16}+\frac{8}{16}+\frac{3}{16}) \\=12+\frac{15}{16} \\=12\frac{15}{16} \text{ft}$
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