## Elementary Technical Mathematics

$12\frac{15}{16} \text{ft}$
Add the given lengths to find the total length of the welded piece:. Total length $=3\frac{1}{4} + 2\frac{3}{8} + 3\frac{1}{8} + 4\frac{3}{16} \\=(3+2+3+4) + (\frac{1}{4}+\frac{3}{8}+\frac{1}{8} + \frac{3}{16}) \\=12+ (\frac{1}{4}+\frac{4}{8}+\frac{3}{16})$ Make the fractions similar using their LCD of $16$ to obtain: Total length $\\=12+(\frac{4}{16}+\frac{8}{16}+\frac{3}{16}) \\=12+\frac{15}{16} \\=12\frac{15}{16} \text{ft}$